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    can anyone explain to me how to calculate this (on attachment)
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    (Original post by tc32)
    can anyone explain to me how to calculate this (on attachment)
    Integrate it using substitution given.
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    (Original post by RDKGames)
    Integrate it using substitution given.
    what about the second part?
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    (Original post by tc32)
    what about the second part?
    It's a modulus of the function; so everything in the negative y flips over to positive y. Imagine 40 of those 'humps' (with area A) going across and you can find out where the last one hits the x-axis, that would be your k\pi
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    Sub kpi and zero into integral and equate it to 40*your A?
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    (Original post by TSRPAV)
    Sub kpi and zero into integral and equate it to 40*your A?
    No need to mess around with any integrals, to be honest, that would just take longer. Observe the pattern of the modulus. If the boundary for A is between 0 and \frac{\pi}{4}, then obviously the boundary for 40A would be between 0 and 40\cdot \frac{\pi}{4}
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    (Original post by RDKGames)
    It's a modulus of the function; so everything in the negative y flips over to positive y. Imagine 40 of those 'humps' (with area A) going across and you can find out where the last one hits the x-axis, that would be your k\pi
    I didn't notice that. Thanks for the help, its a whole lot clearer now.
 
 
 
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