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    A uniform ladder AB mass m rests in equilibrium. . The ladder lies in a vertical plane perpendicular to the wall and makes an acute angle α to the horizontal. A horizontal force P is applied to the ladder in a direction away from and perpendicular to the wall. This force acts at the point one quarter of the way up the ladder. What is the normal force at A
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    A is in contact with a smooth vertical wall and B is in contact with a rough horizontal floor. The ladder lies in a vertical plane perpendicular to the wall and makes an acute angle α to the horizontal. The diagram shows this and the working is my attempt at a sloution I need to find an expression for the normal force at A (the normal force at B is mg ) but i'm a bit stuck , I treied like taking moments but it's not going well
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    I'm a little confused, are the two posts text from the same question, or different parts of the same question?
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    They're the same question I just added more details sorry ! Should've formatted it better
    (Original post by mik1a)
    I'm a little confused, are the two posts text from the same question, or different parts of the same question?
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    (Original post by Pinkberry_y)
    My brother pushed me off a ladder once
    No wonder ,with unhelpful comments like that
 
 
 
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