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# 5b watch

1. how do i do part b?
2. (Original post by jakaloupe)

how do i do part b?
Show that for all real values of a ().
3. (Original post by B_9710)
Show that for all real values of a ().
so if i solve it and find the roots -2+6i and -2-6i then does that prove it? thus has a solution and therefore is non singular
4. (Original post by jakaloupe)
so if i solve it and find the roots -2+6i and -2-6i then does that prove it? thus has a solution and therefore is non singular
Well technically the roots are therefore the for all thus showing that the matrix is non-singular for all real a.
5. (Original post by RDKGames)
Well technically the roots are therefore the for all thus showing that the matrix is non-singular for all real a.
oh ok

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