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# Maths help-functions Watch

1. For f(x)=x^2. domain= -3<x<3.
The range is 0 greater than or equal to f(x) <9
Why is the range greater than or equal to 0. I get why it is less than 9 part of the range
2. (Original post by geography1294)
For f(x)=x^2. domain= -3<x<3.
The range is 0 greater than or equal to f(x) <9
Why is the range greater than or equal to 0. I get why it is less than 9 part of the range
Because y=0 is as low that parabola will go. It touches the x-axis at x=0
3. (Original post by geography1294)
For f(x)=x^2. domain= -3<x<3.
The range is 0 greater than or equal to f(x) <9
Why is the range greater than or equal to 0. I get why it is less than 9 part of the range
Any number squared, regardless of whether it is positive or negative, will be positive; therefore the lowest value of f(x) is 0 squared, which is 0, hence the function's range - as any non-zero number squared will be bigger than 0.
4. (Original post by RDKGames)
Because y=0 is as low that parabola will go. It touches the x-axis at x=0
Oh yeah! sorry for the silly question oops
5. (Original post by some-student)
Any number squared, regardless of whether it is positive or negative, will be positive; therefore the lowest value of f(x) is 0 squared, which is 0, hence the function's range - as any non-zero number squared will be bigger than 0.
Thank you!
6. (Original post by some-student)
Any REAL number squared, regardless of whether it is positive or negative, will be positive; therefore the lowest value of f(x) is 0 squared, which is 0, hence the function's range - as any non-zero REAL number squared will be bigger than 0.
You have to be careful saying stuff like that round here.
7. (Original post by B_9710)
You have to be careful saying stuff like that round here.
Sorry - I completely forgot about that

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