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Simplifying an algebraic faction

Hi Guys,

I'm just starting an algebra course and I've got stuck on one of the introduction questions (attached). I can't seem to simplify it any further than the division of two. Thanks.

(8yx)/6(x^3)(y^2)-4(x)(y^2)
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Masher1346
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Original post by Masher1346
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Think about the numerator and the denominator and what things you could potentially cancel out

Spoiler

What seanFM said.
Original post by Masher1346
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Ah, thank you. I don't know how I couldn't do that before. I've got it down to this now.


Yes, that is now correct :h: well done.

if you had 8f(x,y)(6g(x,y))−4h(x,y) \frac{8f(x,y)}{(6g(x,y)) - 4h(x,y)} then you can take common factors out as you have seen (eg 2) by going

2×4f(x,y)2×(3g(x,y))−2h(x,y) \frac{2\times 4f(x,y)}{ 2 \times (3g(x,y)) - 2h(x,y)} = 22×4f(x,y)(3g(x,y))−2h(x,y) \frac{2}{2} \times \frac{4f(x,y)}{ (3g(x,y)) - 2h(x,y)} where f(x,y), g(x,y) and h(x,y) are not really important for this example, they just represent the different functions that involve x and y eg g(x,y) = x^3y^2

and use similar logic for x and y.
(edited 7 years ago)

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