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    Hi Guys,

    I'm just starting an algebra course and I've got stuck on one of the introduction questions (attached). I can't seem to simplify it any further than the division of two. Thanks.

    (8yx)/6(x^3)(y^2)-4(x)(y^2)
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    (Original post by Masher1346)
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    Think about the numerator and the denominator and what things you could potentially cancel out

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    i.e common factors
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    What seanFM said.
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    (Original post by Masher1346)
    Attachment 576354

    Ah, thank you. I don't know how I couldn't do that before. I've got it down to this now.
    Yes, that is now correct well done.

    if you had  \frac{8f(x,y)}{(6g(x,y)) - 4h(x,y)} then you can take common factors out as you have seen (eg 2) by going

     \frac{2\times 4f(x,y)}{ 2 \times (3g(x,y)) - 2h(x,y)} =  \frac{2}{2} \times  \frac{4f(x,y)}{ (3g(x,y)) - 2h(x,y)} where f(x,y), g(x,y) and h(x,y) are not really important for this example, they just represent the different functions that involve x and y eg g(x,y) = x^3y^2

    and use similar logic for x and y.
 
 
 
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