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C3 JUNE 2013 Q7 part d help don’t understand it Watch

1. Im so sorry but i don’t have space on my laptop to provide a picture of the question but its this one:

http://files.physicsandmathstutor.co...%20Edexcel.pdf

I get how f(x)= 4 and x=6, but i don’t get the jump to x=0.4?

If anyone could provide some sort of help, that would be most appreciated >.<
2. There are two values of x on the graph where f(x) = 4, draw a horizontal line where y=4 and you'll see.

Then you can use similar triangles to work out the value of x.
3. (Original post by unknowntsr)
Im so sorry but i don’t have space on my laptop to provide a picture of the question but its this one:

http://files.physicsandmathstutor.co...%20Edexcel.pdf

I get how f(x)= 4 and x=6, but i don’t get the jump to x=0.4?

If anyone could provide some sort of help, that would be most appreciated >.<
f(x) has two different gradients as you can see. You get x=6 from the line on the right side, and you get x=0.4 from the line on the left. You can work out the equation of the line on the left because you know at least 2 points that it passes through, and then once you have that you can solve it for x by equating it to 4 thus giving you x=0.4.

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