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    Okay guys am having a serious problem in calculating the oxidation numbers of certain elements in a compound....

    e.g what is the oxidation number of POTASSIUM in the compound potassium permanganate?(KMnO4) :please::please: if there are any important procedures that need to be taken care of, please show them up
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    The potassium is +1 as it is In group one. The potassium can take several oxidation states and is the one that normally needs working out whereas almost always, Oxygen is 2- and group ones are +1.
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    (Original post by Ewanclementson)
    The potassium is +1 as it is In group one. The potassium can take several oxidation states and is the one that normally needs working out whereas almost always, Oxygen is 2- and group ones are +1.
    Yeah I get that, what about of Manganese?
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    Hello,

    KMnO4:

    1)Split the compound up into its basic elements so K, Mn, O4
    2)Oxygen's oxidation number is 2- but because there are 4 oxygen atoms then overall for O4 the charge is 8-
    3)Potassium is in group 1 therefore it's oxidation number is 1+
    4)As this compound has no overall charge the oxidation number overall should be 0.
    5) So far you have 8- and 1+
    6) Therefore Mn's oxidation number is 7+ so that all the charges cancel each other out.

    Hope that makes sense!
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    okay now I get the sense of it, Thanks a lot
    (Original post by luckytharm)
    Hello,

    KMnO4:

    1)Split the compound up into its basic elements so K, Mn, O4
    2)Oxygen's oxidation number is 2- but because there are 4 oxygen atoms then overall for O4 the charge is 8-
    3)Potassium is in group 1 therefore it's oxidation number is 1+
    4)As this compound has no overall charge the oxidation number overall should be 0.
    5) So far you have 8- and 1+
    6) Therefore Mn's oxidation number is 7+ so that all the charges cancel each other out.

    Hope that makes sense!
 
 
 
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