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    𝑎𝑥 − 𝑥/𝑏 + 𝑏^2= 𝑎^2 (x)
    2𝑥^2 𝑦 − 5𝑥𝑦 = 3 (y)
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    (Original post by p29)
    𝑎𝑥 − 𝑥 𝑏 + 𝑏 2 = 𝑎 2 (x)
    2𝑥^2 𝑦 − 5𝑥𝑦 = 3 (y)
    Remember that ax+bx = (a+b)x
    That technique is used for both
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    (Original post by p29)
    𝑎𝑥 − 𝑥 𝑏 + 𝑏 2 = 𝑎 2 (x)
    2𝑥^2 𝑦 − 5𝑥𝑦 = 3 (y)
    Re-arrange for what?
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    (Original post by RDKGames)
    Re-arrange for what?
    x and y
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    (Original post by ValerieKR)
    Remember that ax+bx = (a+b)x
    That technique is used for both
    i cant find a common factor for 2 and 5
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    (Original post by p29)
    i cant find a common factor for 2 and 5
    The common factor is y
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    (Original post by ValerieKR)
    The common factor is y
    ugh i wrote the question wrong
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    wtf even is this????????
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    (Original post by p29)
    wtf even is this????????
    ax-\frac{x}{b}+b^2=a^2

    x(a-\frac{1}{b})+b^2=a^2

    You can finish up the rest. It's nothing more complicated than that.
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    Eh, why are you replying? This is the same stupid troll from last time.
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    (Original post by Zacken)
    Eh, why are you replying? This is the same stupid troll from last time.
    Last time?
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    (Original post by RDKGames)
    Last time?
    http://www.thestudentroom.co.uk/show....php?t=4286748
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    (Original post by RDKGames)
    ax-\frac{x}{b}+b^2=a^2

    x(a-\frac{1}{b})+b^2=a^2

    You can finish up the rest. It's nothing more complicated than that.
    thx
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    Oh, forgot that was him there.
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    (Original post by p29)
    :shoot:
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    (Original post by Zacken)
    :shoot:
    :rip:
 
 
 
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