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    Here is the question attached
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    Help anyone
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    Construct a sector from the point C, since they're all radii, all lengths will be 2r, subtract the area of the triangle to find the area of the segment then multiply by 2.
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    Name:  circle.png
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    So you have to work out the area of the sector DCAB, subtract the area of the triangle DCB and multiply it by 2 to get the full area of the overlap.
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    (Original post by NotNotBatman)
    Construct a sector from the point C, since they're all radii, all lengths will be 2r, subtract the area of the triangle to find the area of the segment then multiply by 2.
    Thanks alot man i really appreciate it, but still having a problem in simplifying the answer as exact as in the question :/
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    (Original post by lil_jack)
    Thanks alot man i really appreciate it, but still having a problem in simplifying the answer as exact as in the question :/
    What have you got so far?
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    I remember this question and I remember another method, using the above persons diagram, find sector ADC, multiply by four and subtract two of triangle ADC. If you look at symmetry between the top and bottom halves, they are two overlapping sectors for which the area is the area of both sectors minus any overlap (the central triangle they both share).
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    (Original post by NotNotBatman)
    What have you got so far?
    area of sector= 1/2*4r^2*2/3pie
    area of triangle=1/2*2r*2r*sin(120)
    and then i minus them from each other,,trying to simplify it but gets it wrong
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    (Original post by lil_jack)
    area of sector= 1/2*4r^2*2/3pie
    area of triangle=1/2*2r*2r*sin(120)
    and then i minus them from each other,,trying to simplify it but gets it wrong
    You're right so far, simplifying that;

    Area of sector =  \frac{4}{3} \pi r^2
    Area of triangle =  \sqrt{3} r^2

    Remember when you subtract them, that's only half the area you need and make sure you're calculator is in the right mode (degrees or radians).
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    (Original post by NotNotBatman)
    You're right so far, simplifying that;

    Area of sector =  \frac{4}{3} \pi r^2
    Area of triangle =  \sqrt{3} r^2

    Remember when you subtract them, that's only half the area you need and make sure you're calculator is in the right mode (degrees or radians).
    thanks alot for your time
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    (Original post by JN17)
    I remember this question and I remember another method, using the above persons diagram, find sector ADC, multiply by four and subtract two of triangle ADC. If you look at symmetry between the top and bottom halves, they are two overlapping sectors for which the area is the area of both sectors minus any overlap (the central triangle they both share).
    Good method; another way which I think is the easiest, is to work out the area of sectors DCB and ACB and subtract twice the triangle.
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    (Original post by lil_jack)
    thanks alot for your time
    No problem
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    How did you get the angle CDB as 2π/3
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    How did you get the angle CDB as 2π/3
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    (Original post by GrannyMcPoppins)
    How did you get the angle CDB as 2π/3
    Good Q. Split the triangle into two by drawing a horiz line until it meets its vert base. Pick one: angle @/2, adj side = radius/2, hyp = radius.

    So cos(@/2) = adj/hyp = 1/2, @/2 = 60°, @ = 120°
 
 
 
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