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# C3: Polynomial Division. Watch

1. Chapter: Algebraic Fractions
Mixed Exercise 1E. Question 5.

https://www.biochemtuition.com/wp-co...-fractions.pdf

I can get the answer using long division, but how do i do it using the factor theorem.

F(x)=(Ax^2+Bx+C)(X^2-1)+Dx+E

Is that wrong, if so how do i do it?
2. Eww colour

you let x^2 = 1 and the answer is C
There you compare coefficients for B
3. (Original post by ValerieKR)
Eww colour

you let x^2 = 1 and the answer is C
There you compare coefficients for B
I got D = 3 not C is their something i'm doing wrong? Is it not correct to do F(x)=(Ax^2+Bx+C)(X^2-1)+Dx+E?
4. (Original post by Paranoid_Glitch)
I got D = 3 not C is their something i'm doing wrong? Is it not correct to do F(x)=(Ax^2+Bx+C)(X^2-1)+Dx+E?
Do you mean Q6, not Q5?
5. (Original post by ValerieKR)
Do you mean Q6, not Q5?
Alright now i know i'm messing something up. Still on Question 5, could you do the entire question?
6. (Original post by Paranoid_Glitch)
Alright now i know i'm messing something up. Still on Question 5, could you do the entire question?
Just use long division.
7. (Original post by RDKGames)
Just use long division.
Yeah i know how to. But the person i'm showing wants to know how to do it using the remainder theorem
8. (Original post by Paranoid_Glitch)
Yeah i know how to. But the person i'm showing wants to know how to do it using the factor theorem
The factor theorem just tests whether something is a factor of a function equaling 0. The remainder theorem will get you the remainder. Neither method will give you the full expression.
9. (Original post by Paranoid_Glitch)
Alright now i know i'm messing something up. Still on Question 5, could you do the entire question?
For Q5:

- now expand and compare coefficients.
10. (Original post by Zacken)
For Q5:

- now expand and compare coefficients.
Why just (X^2+B) and not (Ax^2 + Bx +C) ?
11. (Original post by Paranoid_Glitch)
Why just (X^2+B) and not (Ax^2 + Bx +C) ?
Are we looking at the same question?

It say to find such that . Multiply both sides by to turn it into a polynomial identity:

I'm really not sure where your A,B, C has come from...

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