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    60√110
    ------------
    6√10

    How do i simplify this??
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    (Original post by Chelsea12345)
    60√110
    ------------
    6√10

    How do i simplify this??
    Rationalise the denominator. What can you multiply it by to make it an integer?
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    (Original post by RDKGames)
    Rationalise the denominator. What can you multiply it by to make it an integer?
    Do you rationalise by multiplying everything 6√10?
    I got √1100 as the answer but mymaths says the answer is wrong??
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    (Original post by Chelsea12345)
    Do you rationalise by multiplying everything 6√10?
    I got √1100 as the answer but mymaths says the answer is wrong??
    You could, but it's just simpler to multiply top and bottom by root 10 as then the denominator will rationalise.
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    (Original post by RDKGames)
    You could, but it's just simpler to multiply top and bottom by root 10 as then the denominator will rationalise.
    Thankyou!!!!!
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    ^lol wat, why are we rationlising?

    Just note that \sqrt{110} = \sqrt{11 \times 10} = \sqrt{11}\sqrt{10} so we get \displaystyle \frac{60\sqrt{11}\sqrt{10}}{\, 6\sqrt{10}} = \cdots
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    (Original post by Zacken)
    ^lol wat, why are we rationlising?

    Just note that \sqrt{110} = \sqrt{11 \times 10} = \sqrt{11}\sqrt{10} so we get \displaystyle \frac{60\sqrt{11}\sqrt{10}}{\, 6\sqrt{10}} = \cdots
    Also an acceptable method. Nothing wrong with a little bit of a longer path to the answer from time to time.

    Mymaths is just being picky.
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    (Original post by RDKGames)
    Also an acceptable method. Nothing wrong with a little bit of a longer path to the answer from time to time.
    I've become lazy as of late.
 
 
 
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