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how to rearrange? and get x Watch

1. 1.
−4−(3−𝑥)/(2−𝑎)=(6−5𝑥)/(−𝑎+1)
2.
(2𝑥+5)/3+(𝑥−2)/5= 2𝑥
3.
4/(2𝑥−3)−𝑦/(2−𝑥)= 3𝑥 − 1
plzzz help
2. (Original post by p29)
1.
−4−(3−𝑥)/(2−𝑎)=(6−5𝑥)/(−𝑎+1)
2.
(2𝑥+5)/3+(𝑥−2)/5= 2𝑥
3.
4/(2𝑥−3)−𝑦/(2−𝑥)= 3𝑥 − 1
plzzz help
Add/subtract the fractions before multiplying both sides by the denominator.

Or multiply through the equations by the denominators. Then proceed to solve for x.
3. (Original post by RDKGames)
Add/subtract the fractions before multiplying both sides by the denominator.

Or multiply through the equations by the denominators. Then proceed to solve for x.
how do you add/subtract the fractions when there are different variables in the denominator?
4. (Original post by p29)
how do you add/subtract the fractions when there are different variables in the denominator?
Just algebraic manipulation.

If you let a, b, c and d equal anything you want; then
5. (Original post by p29)
1.
−4−(3−𝑥)/(2−𝑎)=(6−5𝑥)/(−𝑎+1)
Assuming you mean

Multiply both sides by .
6. (Original post by RDKGames)
Just algebraic manipulation.

If you let a, b, c and d equal anything you want; then
Isn't it?

EDIT:You just changed it.
7. (Original post by alexjones1994)
Isn't it?
Typo, I edited it before you posted that lol.
8. (Original post by Zacken)
Assuming you mean

Multiply both sides by .
no the -4 is on the fraction
9. (Original post by p29)
no the -4 is on the fraction
Okay, same advice applies though.
10. (Original post by Zacken)
Okay, same advice applies though.
thank you

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