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    Write it in the form y=ax^2 + bx + c

    Name:  Screen Shot 2016-09-09 at 18.54.13.png
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    Substitute in x=0 and you get ... c = 18

    Substitue x and y in from the turning point and I got
    2a + b = -4

    I think I'm meant to come across a similar phrase that I can use simultaneous equations to find a and b. But as there are no roots, I'm not sure what to do. Any guidance please
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    Hint: There is another place you can find where y=18, the parabola is symmetrical about the line x=2
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    (Original post by Sal.Tek_ 〔サルテック〕)
    Hint: There is another place you can find where y=18, the parabola is symmetrical about the line x=2
    Still not sure, there must be a gap in my knowledge.
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    (Original post by Feynboy)
    ...
    You've got to understand the mathematical information you're using to try to get the values of a,b,c.

    You've correctly used the fact that the intercept is 18 to get c=18, which is good.
    But then you used the fact that the point (2,10) lies on the parabola. Notice how just this information gives rise to many different parabolas, all with intercept 18 and passing through (2,10).

    The key piece of information in the diagram that makes the parabola unique (and hence you can find the exact values of a,b,c) is that (2, 10) is the turning point of the parabola; it's not just a point that lies on the parabola.

    So use what you know about turning points to achieve this: "I think I'm meant to come across a similar phrase that I can use simultaneous equations to find a and b."
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    Name:  MathsQuad2.png
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    As you can see there is another point you can derive, (4,18), you can use this to solve a pair of simultaneous equations with x and y
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    (Original post by IrrationalRoot)
    You've got to understand the mathematical information you're using to try to get the values of a,b,c.

    You've correctly used the fact that the intercept is 18 to get c=18, which is good.
    But then you used the fact that the point (2,10) lies on the parabola. Notice how just this information gives rise to many different parabolas, all with intercept 18 and passing through (2,10).

    The key piece of information in the diagram that makes the parabola unique (and hence you can find the exact values of a,b,c) is that (2, 10) is the turning point of the parabola; it's not just a point that lies on the parabola.

    So use what you know about turning points to achieve this: "I think I'm meant to come across a similar phrase that I can use simultaneous equations to find a and b."
    I know a(x-h) + k gives the turning point but... ?
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    (Original post by Sal.Tek_ 〔サルテック〕)
    Name:  MathsQuad2.png
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    As you can see there is another point you can derive, (4,18), you can use this to solve a pair of simultaneous equations with x and y

    This was one way, thank you.
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    (Original post by Feynboy)
    This was one way, thank you.
    Another way is by differentiating and making use of the fact that y'(2) = 0 as per IrrationalRoot's comment.
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    (Original post by Feynboy)
    Write it in the form y=ax^2 + bx + c

    Name:  Screen Shot 2016-09-09 at 18.54.13.png
Views: 54
Size:  127.1 KB

    Substitute in x=0 and you get ... c = 18

    Substitue x and y in from the turning point and I got
    2a + b = -4

    I think I'm meant to come across a similar phrase that I can use simultaneous equations to find a and b. But as there are no roots, I'm not sure what to do. Any guidance please
    (2,10) is a turning point, so differentiate the equation, set it equal to 0 and then substitute in the values x=2 and y=10.
 
 
 
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