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# A level Physics help - Dimensionally correct Watch

1. How do you show that the period of a pendulum is dimensionally correct?

T=2pi square root(l/g)
This is where I am stuck,
s=2pi square root (m m^-1s^-2)

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2. If the units of g are m s^-2, then the units of 1/g are m^-1 s^2. This would change your unit equation to;

s=2pi square root (m m^-1s^2)

Now - combine the two lenght units - what do you get? What does that leave you with? Take the square root and you should be done.
3. (Original post by Pangol)
If the units of g are m s^-2, then the units of 1/g are m^-1 s^2. This would change your unit equation to;

s=2pi square root (m m^-1s^2)

Now - combine the two lenght units - what do you get? What does that leave you with? Take the square root and you should be done.
Thank you so much I actually understand 😊

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