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    How do you show that the period of a pendulum is dimensionally correct?

    T=2pi square root(l/g)
    This is where I am stuck,
    s=2pi square root (m m^-1s^-2)
    I am unsure of if the negative powers are needed, please help?


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    If the units of g are m s^-2, then the units of 1/g are m^-1 s^2. This would change your unit equation to;

    s=2pi square root (m m^-1s^2)

    Now - combine the two lenght units - what do you get? What does that leave you with? Take the square root and you should be done.
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    (Original post by Pangol)
    If the units of g are m s^-2, then the units of 1/g are m^-1 s^2. This would change your unit equation to;

    s=2pi square root (m m^-1s^2)

    Now - combine the two lenght units - what do you get? What does that leave you with? Take the square root and you should be done.
    Thank you so much I actually understand 😊


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