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    Hi can someone explain how to do this please?

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    \frac{2x +5}{x+3} = \frac{A(x+3)}{x+3} + \frac{B}{x+3}

    Hope that helps, jessyjellytot14
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    (Original post by jessyjellytot14)
    Hi can someone explain how to do this please?

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Views: 45
Size:  23.6 KB


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    You can multiply both sides of the identity by (x+3) then proceed to expand and compare coefficients in terms of A and B because they must be the same on both sides of the identity.
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    (Original post by RDKGames)
    You can multiply both sides of the identity by (x+3) then proceed to expand and compare coefficients in terms of A and B because they must be the same on both sides of the identity.
    Okay I tried multiplying each side by (x+3) but i'm not sure if you meant like this...
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    When I compare the coefficients I just end up with 2x+5/x+3 again or something that is not on the mark scheme


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    (Original post by jessyjellytot14)
    Okay I tried multiplying each side by (x+3) but i'm not sure if you meant like this...
    Name:  ImageUploadedByStudent Room1473519891.374618.jpg
Views: 36
Size:  59.1 KB

    When I compare the coefficients I just end up with 2x+5/x+3 again or something that is not on the mark scheme


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    You multiplied the denominator by (x+3), no need to do that. Just multiply both sides of the identity by the denominator of the LHS so you can lose it.
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    (Original post by RDKGames)
    You multiplied the denominator by (x+3), no need to do that. Just multiply both sides of the identity by the denominator of the LHS so you can lose it.
    Okay thanks- Once you have the quotient and remainder, can you write it in the form: Quotient + Remainder/ x+3 ?
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    (Original post by jessyjellytot14)
    Okay thanks- Once you have the quotient and remainder, can you write it in the form: Quotient + Remainder/ x+3 ?
    When you find your values of A and B then yeah, just plug them into identity.
 
 
 
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