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    I have no idea how to do this question... so any help would be highly appreciated!

    Ethanedioic acid, H2C2O4, is a reducing agent. On reaction with manganate the H2C2O4 is oxidised to CO2 and the MnO4- reduced to Mn2+. A sample of hydrated ethanedioic acid, H2C2O4.xH2O, weighing 0.980g was dissolved in water and the solution made up to 250cm3. 25cm3 samples of the solution were transferred to a conical flask and titrated with 0.01moldm-3 potassium manganate (VII). The ethanedioic acid in the solution required 31.1cm3 of the potassium manganate (VII) solution for reaction. Calculate the value of x, the number of waters of crystallisation.

    Thanks in advance.
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    (Original post by cassie05)
    I have no idea how to do this question... so any help would be highly appreciated!

    Ethanedioic acid, H2C2O4, is a reducing agent. On reaction with manganate the H2C2O4 is oxidised to CO2 and the MnO4- reduced to Mn2+. A sample of hydrated ethanedioic acid, H2C2O4.xH2O, weighing 0.980g was dissolved in water and the solution made up to 250cm3. 25cm3 samples of the solution were transferred to a conical flask and titrated with 0.01moldm-3 potassium manganate (VII). The ethanedioic acid in the solution required 31.1cm3 of the potassium manganate (VII) solution for reaction. Calculate the value of x, the number of waters of crystallisation.

    Thanks in advance.
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