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# Help solving this Matrix question watch

1. I am pretty sure I know how to do the question just unsure about It's lay out. If someone could solve it and show their working that would help me understand a great deal.

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2. For part a:
is the transpose of the matrix . In the transpose of a matrix the rows become the columns and the columns become the rows. Using this idea you should be able to find the transpose.

For part b:
Just find the product - however be careful as matrices are not commutative. i.e.

For part c:
Find the determinant and then do one over the determinant multiplied by a rearranged matrix (do you know how it should be rearranged?).

Hope this helps
3. (Original post by Trackstar)
I am pretty sure I know how to do the question just unsure about It's lay out. If someone could solve it and show their working that would help me understand a great deal.

(a) (i) Simply write down the transpose matrix (I trust you know how). No working or anything needed of course.
(ii) Write out AA^T, i.e. the two matrices next to each other in that order, then it will be best to show some intermediate steps in the multiplication (e.g. showing the adding of the different multiplied parts)
(iii) Trivial (remember that AA^-1 = I and A^-1A = I)
4. (Original post by Cryptokyo)
For part a:
is the transpose of the matrix . In the transpose of a matrix the rows become the columns and the columns become the rows. Using this idea you should be able to find the transpose.

For part b:
Just find the product - however be careful as matrices are not commutative. i.e.

For part c:
Find the determinant and then do one over the determinant multiplied by a rearranged matrix (do you know how it should be rearranged?).

Hope this helps
Awesome got it!
5. (Original post by 13 1 20 8 42)
(a) (i) Simply write down the transpose matrix (I trust you know how). No working or anything needed of course.
(ii) Write out AA^T, i.e. the two matrices next to each other in that order, then it will be best to show some intermediate steps in the multiplication (e.g. showing the adding of the different multiplied parts)
(iii) Trivial (remember that AA^-1 = I and A^-1A = I)
thanks, helped a lot

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Updated: September 11, 2016
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