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    Can anyone plz tell me how to solve the problem below:

    pH of the mixture formed when 25 cm3 of 2 mol dm-3 NaOH solution is added to 50 cm3 of 2 mol dm-3 CH3COOH, for which Ka = 1.7 x 10^-5 mol dm-3.

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    (Original post by lmao-_-)
    Can anyone plz tell me how to solve the problem below:

    pH of the mixture formed when 25 cm3 of 2 mol dm-3 NaOH solution is added to 50 cm3 of 2 mol dm-3 CH3COOH, for which Ka = 1.7 x 10^-5 mol dm-3.

    Cheers.
    Remember that acid + base ==> salt + water.

    You need to work out the number of moles of NaOH and CH3COOH and write down a balanced symbol equation for the reaction. You then need to work out how much CH3COOH you have left. If you know the amounts of CH3COOH and CH3COO- you can work out the pH.
 
 
 
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