Hey there! Sign in to join this conversationNew here? Join for free
    • Thread Starter
    Offline

    10
    ReputationRep:
    Hello there. I have searched up any sort of method to work out the following, but I am unsure on how to word it. Can someone offer me a method as my teacher has not really told me.

    The mean of five numbers is 5 and the median is 6. List the numbers

    I'm not asking for the answer, but a method. Many thanks! Also, if you do not have anything helpful or nice to say, do not say it all.
    Offline

    18
    ReputationRep:
    (Original post by melissadh)
    Hello there. I have searched up any sort of method to work out the following, but I am unsure on how to word it. Can someone offer me a method as my teacher has not really told me.

    The mean of five numbers is 5 and the median is 6. List the numbers

    I'm not asking for the answer, but a method. Many thanks! Also, if you do not have anything helpful or nice to say, do not say it all.
    The number in the middle of the list is 6 , what must the 5 numbers add up to ?
    The method really is just trial an error to pick a set of numbers that works


    Posted from TSR Mobile
    Offline

    3
    ReputationRep:
    If there are 5 numbers, the middle number will have to be the median, so the set will look like this in ascending order:

    a, b, 6, c, d

    For the mean to be 5, all of the numbers added together divided by the amount of numbers must equal 5, therefore (a+b+6+c+d) / 5 = 5. Can you take it from there?
    Offline

    2
    ReputationRep:
    (Original post by bobbobson)
    if there are 5 numbers, the middle number will have to be the median, so the set will look like this in ascending order:

    A, b, 6, c, d

    for the mean to be 5, all of the numbers added together divided by the amount of numbers must equal 5, therefore (a+b+6+c+d) / 5 = 5. Can you take it from there?
    can't barage
    the farage
    • Thread Starter
    Offline

    10
    ReputationRep:
    How do you know there are 5 numbers? I can't take it on there! Nice with the Farage bu the way and thanks for the response.
    Offline

    3
    ReputationRep:
    In your OP, you said the mean of 5 numbers is 5, it says in the question there is 5 numbers. To continue where I left off, rearrange the equation so you get a + b + c + d = on the left hand side

    Posted from TSR Mobile
    • Thread Starter
    Offline

    10
    ReputationRep:
    Aha! Yes! OK. Sorry. I did indeed think of that. So I'd end up with:

    a+b+c+d = -5
    • Community Assistant
    • Welcome Squad
    Offline

    20
    ReputationRep:
    (Original post by melissadh)
    Aha! Yes! OK. Sorry. I did indeed think of that. So I'd end up with:

    a+b+c+d = -5
    No, try again. You're multiplying both sides by 5 then subtracting 6.
    • Thread Starter
    Offline

    10
    ReputationRep:
    (Original post by RDKGames)
    No, try again. You're multiplying both sides by 5 then subtracting 6.
    a+b+c+d = 19

    So they all up to 19. I suppose I know have to use trial and error to get such a mean of 5?
    • Community Assistant
    • Welcome Squad
    Offline

    20
    ReputationRep:
    (Original post by melissadh)
    a+b+c+d = 19

    So they all up to 19. I suppose I know have to use trial and error to get such a mean of 5?
    Huh? No you already used the mean to get to this point.

    a, b, 6, c, d

    So you know a and b must be less than 6 while c and d must be more then 6. Just try some numbers

    a+b+c+d=19

    One such possibility is a=1, b=2, c=7, d=9. There are more, I'm not sure what your questions asks for.
    • Thread Starter
    Offline

    10
    ReputationRep:
    Wow! I just learnt something new! Thank you so much! I got it from here!
 
 
 
  • See more of what you like on The Student Room

    You can personalise what you see on TSR. Tell us a little about yourself to get started.

  • Poll
    Brussels sprouts
    Useful resources

    Make your revision easier

    Maths

    Maths Forum posting guidelines

    Not sure where to post? Read the updated guidelines here

    Equations

    How to use LaTex

    Writing equations the easy way

    Student revising

    Study habits of A* students

    Top tips from students who have already aced their exams

    Study Planner

    Create your own Study Planner

    Never miss a deadline again

    Polling station sign

    Thinking about a maths degree?

    Chat with other maths applicants

    Can you help? Study help unanswered threads

    Groups associated with this forum:

    View associated groups
  • See more of what you like on The Student Room

    You can personalise what you see on TSR. Tell us a little about yourself to get started.

  • The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

    Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

    Quick reply
    Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.