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    If x=acosec, y=bcot and z=csec
    Simplify x/x^2-a^2
    I've got to cosec/acot^2 (not sure if this is right) but don't know where to go from here. Thanks!
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    Where are the arguments? The cosec of what?
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    Let's assume the arguments are \theta, what you have done is correct, but you can write \frac{cosec(\theta)}{acot^2 (\theta)} in a nicer form if you express it in terms of sin and cos and simplify.
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    How is the a from the bottom cancelled out?
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    (Original post by Jamesphillll)
    How is the a from the bottom cancelled out?
    Oh, it's not, just a typo.
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    (Original post by NotNotBatman)
    Oh, it's not, just a typo.
    Still unsure of what to do from here :/
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    (Original post by Jamesphillll)
    Still unsure of what to do from here :/
    I'm sure you could leave it, but if you want to simplify it, note that \frac{cosec(\theta)}{acot^2 (\theta)} = \frac{1}{a} \times\frac{cosec(\theta)}{cot^2 (\theta)}

    Now, write  cosec(\theta) and cot^2(\theta) in terms of  sin(\theta) and cos(\theta)
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    (Original post by NotNotBatman)
    I'm sure you could leave it, but if you want to simplify it, note that \frac{cosec(\theta)}{acot^2 (\theta)} = \frac{1}{a} \times\frac{cosec(\theta)}{cot^2 (\theta)}

    Now, write  cosec(\theta) and cot^2(\theta) in terms of  sin(\theta) and cos(\theta)
    Thanks, that makes more sense now
 
 
 
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