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    if you were to have as an example: C=2(x+a)

    If the answer is C-2a/2

    Why can this not be written as C/2-a
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    (Original post by JackLeggett)
    if you were to have as an example: C=2(x+a)

    If the answer is C-2a/2

    Why can this not be written as C/2-a
    It can be written that way. They are exactly the same.
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    (Original post by JackLeggett)
    if you were to have as an example: C=2(x+a)

    If the answer is C-2a/2

    Why can this not be written as C/2-a
    They can but writing it as C-2a/2 is clearer so preferred
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    (Original post by JackLeggett)
    if you were to have as an example: C=2(x+a)

    If the answer is C-2a/2

    Why can this not be written as C/2-a
    \displaystyle \frac{C-2a}{2}=\frac{C}{2}-\frac{2a}{2}=\frac{C}{2}-a
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    same ting
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    (Original post by abc_123_)
    They can but writing it as C-2a/2 is clearer so preferred
    Thanks for help. When the equation is C=2 √h(2x-h). ( √h(2x-h) is all rooted) I have got it down to c^2/4=h(2x-h), where do I go from here?
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    (Original post by JackLeggett)
    Thanks for help. When the equation is C=2 √h(2x-h). ( √h(2x-h) is all rooted) I have got it down to c^2/4=h(2x-h), where do I go from here?
    What are you trying to do?
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    (Original post by B_9710)
    What are you trying to do?
    Sorry, make x the subject, I have c^2/2h+h/2=x is this correct
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    (Original post by JackLeggett)
    Thanks for help. When the equation is C=2 √h(2x-h). ( √h(2x-h) is all rooted) I have got it down to c^2/4=h(2x-h), where do I go from here?
    Can u Write down the whole equation please xx
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    (Original post by abc_123_)
    Can u Write down the whole equation please xx


    I have solved it to



    is this correct??
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    (Original post by JackLeggett)


    I have solved it to



    is this correct??
    Nope. What happens to the 2 in front of the root when you square both sides? You seemed to have ignored it completely.
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    (Original post by JackLeggett)


    I have solved it to



    is this correct??
    I think that's right x
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    (Original post by abc_123_)
    Yea that's right xx
    Well done
    Nope.
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    (Original post by RDKGames)
    Nope.
    What?
    I got two answers:
    First attempt = c^2 / 8h
    2nd attempt = c^2 / 2h
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    (Original post by abc_123_)
    What?
    It's incorrect and you said it's correct.
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    (Original post by RDKGames)
    It's incorrect and you said it's correct.
    I thought it was … sorry
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    (Original post by RDKGames)
    Nope. What happens to the 2 in front of the root when you square both sides? You seemed to have ignored it completely.
    ?? I divided C by the 2 in front of the root?? Also I posted this question on another thread with the same answer and you said it was correct, I am not being rude I am just confused??
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    (Original post by JackLeggett)
    ?? I divided C by the 2 in front of the root?? Also I posted this question on another thread with the same answer and you said it was correct, I am not being rude I am just confused??
    I said it was correct because you the way you wrote the question made me miss out on the 2 as it was so close to the equals sign while the rest of the equation was separated by a space hence I ignored it so your answer was correct in that case. I edited that comment soon after I saw your post here and noticed the 2 in front.

    Okay so you divide by 2, still didn't get the right answer as you didn't square LHS properly.
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    (Original post by JackLeggett)
    ?? I divided C by the 2 in front of the root?? Also I posted this question on another thread with the same answer and you said it was correct, I am not being rude I am just confused??
    Correct answer is  x=\frac{c^2+4h^2}{8h} , of course there are alternative forms that are equivalent to this.
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    (Original post by RDKGames)
    I said it was correct because you the way you wrote the question made me miss out on the 2 as it was so close to the equals sign while the rest of the equation was separated by a space hence I ignored it so your answer was correct in that case. I edited that comment soon after I saw your post here and noticed the 2 in front.

    Okay so you divide by 2, still didn't get the right answer as you didn't square LHS properly.
    Oh Ok thanks
 
 
 
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