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# Rearranging Help Watch

1. if you were to have as an example: C=2(x+a)

Why can this not be written as C/2-a
2. (Original post by JackLeggett)
if you were to have as an example: C=2(x+a)

Why can this not be written as C/2-a
It can be written that way. They are exactly the same.
3. (Original post by JackLeggett)
if you were to have as an example: C=2(x+a)

Why can this not be written as C/2-a
They can but writing it as C-2a/2 is clearer so preferred
4. (Original post by JackLeggett)
if you were to have as an example: C=2(x+a)

Why can this not be written as C/2-a
5. same ting
6. (Original post by abc_123_)
They can but writing it as C-2a/2 is clearer so preferred
Thanks for help. When the equation is C=2 √h(2x-h). ( √h(2x-h) is all rooted) I have got it down to c^2/4=h(2x-h), where do I go from here?
7. (Original post by JackLeggett)
Thanks for help. When the equation is C=2 √h(2x-h). ( √h(2x-h) is all rooted) I have got it down to c^2/4=h(2x-h), where do I go from here?
What are you trying to do?
8. (Original post by B_9710)
What are you trying to do?
Sorry, make x the subject, I have c^2/2h+h/2=x is this correct
9. (Original post by JackLeggett)
Thanks for help. When the equation is C=2 √h(2x-h). ( √h(2x-h) is all rooted) I have got it down to c^2/4=h(2x-h), where do I go from here?
Can u Write down the whole equation please xx
10. (Original post by abc_123_)
Can u Write down the whole equation please xx
$C=2\sqrt{h(2x-h)}$

I have solved it to

$\frac{C^2}{2h}+\frac{h}{2}=x$

is this correct??
11. (Original post by JackLeggett)
$C=2\sqrt{h(2x-h)}$

I have solved it to

$\frac{C^2}{2h}+\frac{h}{2}=x$

is this correct??
Nope. What happens to the 2 in front of the root when you square both sides? You seemed to have ignored it completely.
12. (Original post by JackLeggett)
$C=2\sqrt{h(2x-h)}$

I have solved it to

$\frac{C^2}{2h}+\frac{h}{2}=x$

is this correct??
I think that's right x
13. (Original post by abc_123_)
Yea that's right xx
Well done
Nope.
14. (Original post by RDKGames)
Nope.
What?
First attempt = c^2 / 8h
2nd attempt = c^2 / 2h
15. (Original post by abc_123_)
What?
It's incorrect and you said it's correct.
16. (Original post by RDKGames)
It's incorrect and you said it's correct.
I thought it was … sorry
17. (Original post by RDKGames)
Nope. What happens to the 2 in front of the root when you square both sides? You seemed to have ignored it completely.
?? I divided C by the 2 in front of the root?? Also I posted this question on another thread with the same answer and you said it was correct, I am not being rude I am just confused??
18. (Original post by JackLeggett)
?? I divided C by the 2 in front of the root?? Also I posted this question on another thread with the same answer and you said it was correct, I am not being rude I am just confused??
I said it was correct because you the way you wrote the question made me miss out on the 2 as it was so close to the equals sign while the rest of the equation was separated by a space hence I ignored it so your answer was correct in that case. I edited that comment soon after I saw your post here and noticed the 2 in front.

Okay so you divide by 2, still didn't get the right answer as you didn't square LHS properly.
19. (Original post by JackLeggett)
?? I divided C by the 2 in front of the root?? Also I posted this question on another thread with the same answer and you said it was correct, I am not being rude I am just confused??
Correct answer is , of course there are alternative forms that are equivalent to this.
20. (Original post by RDKGames)
I said it was correct because you the way you wrote the question made me miss out on the 2 as it was so close to the equals sign while the rest of the equation was separated by a space hence I ignored it so your answer was correct in that case. I edited that comment soon after I saw your post here and noticed the 2 in front.

Okay so you divide by 2, still didn't get the right answer as you didn't square LHS properly.
Oh Ok thanks

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