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    I really have no idea how to do this question and any guidance/help would be much appreciated!!Name:  image.jpg
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    (Original post by Sukjeetsandhu)
    I really have no idea how to do this question and any guidance/help would be much appreciated!!
    Well a good start would be labeling angles and sides. I proved this with side lengths only, though you can use angles too.
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    How did you get to your answer?? Thanks
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    (Original post by Sukjeetsandhu)
    How did you get to your answer?? Thanks
    Rotated but essentially the same. I labelled it like this:

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    We know that A=B=\frac{1}{2}bc

    We can find c because c^2=a^2-b^2

    So A=B=\frac{1}{2}b\sqrt{a^2-b^2}

    Therefore A+B=b\sqrt{a^2-c^2}

    From here on in, find distance d in terms of a and b from the fact that d=b-c. You should find that C=\frac{1}{2}d^2.

    Then once you got C in terms of a and b, notice that a^2=2d^2. This should give you enough info to show that A+B=C

    Have a go let me know how you do. Probably easier to do by angles but I haven't tried it.

    NOTE: I forgot to label area C but you can do that yourself.
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    (Original post by Sukjeetsandhu)
    I really have no idea how to do this question and any guidance/help would be much appreciated!!Name:  image.jpg
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Size:  500.0 KB
    Alternatively you know enough to work out all of the angles. If the side of the equilateral triangle is x, you can write down the areas of the triangles in terms of x. You'll need to use sin 2A = 2 sin A cos A at some point.

    Have a go at this method.
 
 
 
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