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    Find the equation of the tangent to the curve y = 50 / ( 2x +1 )^2 at the point (3,2), giving your answer in the form ax + by + c = 0, where a, b and c are integers

    is this correct??
    y = 50 ( 2x -1 ) ^-2

    dy/dx = -200( 2x - 1)^-3

    so 8x + 5y -34 = 0
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    (Original post by Custardcream000)
    Find the equation of the tangent to the curve y = 50 / ( 2x +1 )^2 at the point (3,2), giving your answer in the form ax + by + c = 0, where a, b and c are integers

    is this correct??
    y = 50 ( 2x -1 ) ^-2

    dy/dx = -200( 2x - 1)^-3

    so 8x + 5y -34 = 0
    What check can you do to make sure your answer is right?
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    (Original post by SeanFM)
    What check can you do to make sure your answer is right?
    plug the coordinate in

    forgot lol
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    (Original post by Custardcream000)
    plug the coordinate in

    forgot lol
    Correct. After that I would just look at the differentiation again with fresh eyes and that you've found the correct value for dy/dx, but yes, it looks right.
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    (Original post by SeanFM)
    Correct. After that I would just look at the differentiation again with fresh eyes and that you've found the correct value for dy/dx, but yes, it looks right.
    thankyou
 
 
 
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