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    • Thread Starter
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    Hi guys I'm stuck own differentiation of x=cos(y/2) +1
    would help if someone explained each step I don't understand why it is
    -1/2sin(y/2)
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    Use the chain rule.

    let u = y/2 and find \frac{dx}{du} \times \frac{du}{dy}
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    (Original post by NotNotBatman)
    Use the chain rule.

    let u = y/2 and find \frac{dx}{du} \times \frac{du}{dy}
    Thanks but what would u' would be
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    (Original post by Wisteria_xo)
    Hi guys I'm stuck own differentiation of x=cos(y/2) +1
    would help if someone explained each step I don't understand why it is
    -1/2sin(y/2)
    Name:  14423787_1183282905028109_1835826934_o.jpg
Views: 26
Size:  54.8 KB


    omg i'm procrastinating so hard that i'm answering maths questions wtf is my life
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    (Original post by Wisteria_xo)
    Thanks but what would u' would be
    Is it Easier to see if written like this.  u = \frac{1}{2}y ?
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    (Original post by Rhaenys10)
    Name:  14423787_1183282905028109_1835826934_o.jpg
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    omg i'm procrastinating so hard that i'm answering maths questions wtf is my life
    lool AH MAKES SO MUCH SENSE thank you !
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    (Original post by NotNotBatman)
    Is it Easier to see if written like this.  u = \frac{1}{2}y ?
    yes yes yes helped a lot thank you!!! Blind moment !
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    (Original post by Wisteria_xo)
    lool AH MAKES SO MUCH SENSE thank you !
    you're welcome
 
 
 
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