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    5.00 g of a mixture of MgSO4.7H2O and CuSO4.5H2O was heated at 120C until a mixture of the anhydrous salts was formed, which weighed 3.00 g. Calculate the percentage by mass of MgSO4.7H2O in the mixture.

    How would i do this question (method)?
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    (Original post by 12345abbbc)
    5.00 g of a mixture of MgSO4.7H2O and CuSO4.5H2O was heated at 120C until a mixture of the anhydrous salts was formed, which weighed 3.00 g. Calculate the percentage by mass of MgSO4.7H2O in the mixture.

    How would i do this question (method)?

    



\begin{align}



\text{MgSO}_4 \cdot 7\text{H}_2\text{O} &\rightarrow \text{MgSO}_4 + 7\text{H}_2\text{O} \\



\text{CuSO}_4 \cdot 5 \text{H}_2\text{O} &\rightarrow \text{CuSO}_4 + 5\text{H}_2\text{O} \\



\therefore \underbrace{\text{MgSO}_4 \cdot \text{7H}_2\text{O} + \text{CuSO}_4 \cdot 5\text{H}_2\text{O}}_{\textbf{5g  }}\rightarrow \underbrace{\text{CuSO}_4 +\text{MgSO}_4}_{\textbf{3g}} +\underbrace{12\text{H}_2\text{O  }}_{\textbf{2g}}



  



\end{align}

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    (Original post by Kvothe the Arcane)

    



\begin{align}



\text{MgSO}_4 \cdot 7\text{H}_2\text{O}  &\rightarrow \text{MgSO}_4 + 7\text{H}_2\text{O} \\



\text{CuSO}_4 \cdot 5 \text{H}_2\text{O}   &\rightarrow \text{CuSO}_4 + 5\text{H}_2\text{O}



\end{align}
    FTFY
 
 
 
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