HELP with chemistry; number of particles/molecules/atoms

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    I have a rough understanding of working this out: Work out number of moles by doing mass/Mr, then multiplying the number of moles with Na(6.02*10^23).

    "Calculate number of moles for phosphorus(III) chloride: PCl3" I got 1.204*10^23

    "....atoms in 3.55g of chlorine:Cl2" How would I do this one?
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    (Original post by Perfection Ace)
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    If i remember correctly, you first find the moles so

    3.55/Mr Mr of Cl2= (35.5 x2) =71 so
    3.55/71 = 0.04733 mole
    then times moles by avagadros constant (6.023x10^23)

    so 0.04733 x 6.023x10^23 = whatever.

    this gives you the number of cl2 in one mole.

    its been a while >.< gl
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    (Original post by ranz)
    If i remember correctly, you first find the moles so

    3.55/Mr Mr of Cl2= (35.5 x2) =71 so
    3.55/71 = 0.04733 mole
    then times moles by avagadros constant (6.023x10^23)

    so 0.04733 x 6.023x10^23 = whatever.

    this gives you the number of cl2 in one mole.

    its been a while >.< gl
    That's what I thought too! But it's Cl2? So don't I multiply or divide by 2 or something......
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    (Original post by Perfection Ace)
    That's what I thought too! But it's Cl2? So don't I multiply or divide by 2 or something......
    well, u would divide the moles by 2 only if they ask for number of atoms of Cl in Cl2 ,
    however if they ask number of molecules of cl2 in x grams, then u dont divide.


    u DONT divide grams and then find moles noo! u find moles then divide by 2.

    example q:number of atoms of S in S8 as 2grams,
    you find mole of S8 so: g/mr > 2/(8x32.1) = 0.25 mol
    then u divide 0.25/8 =0.0311 mol [for one S]

    then 0.0311 mol x avagadros constant for number of atoms of S in 2g of S8


    but i advice u also ask ur teacher, its been a while since i did chem but from what i can remember this is how its done.


    if they ask for ex. for number of molecules of S8 in x grams, then u do the method i mentioned before.



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