Algebra? Find x

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    Three times the reciprocal of a number is one less than ten times the number. What is the number and how would I approach? I think it is 3(1/x) = 10x-1 but I'm not sure how to solve it?
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    There are 2 solutions... (start by getting rid of the brackets and then multiply both sides by x, then rearrange and solve the quadractic formula
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    You're on the right track. Just multiply all terms by x to get 10x2 - x - 3 = 0 and factorise.
    (5x-3)(2x+1) = 0
    so x = 3/5 or -1/2
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    Thank you for the reply, the part I don't get is how to multiply the first part by x ?
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    (Original post by RenovationDev)
    Thank you for the reply, the part I don't get is how to multiply the first part by x ?
    Quite simply.

    3(\frac{1}{x})=10x-1

    \Rightarrow 3x(\frac{1}{x})=x(10x-1)

    \Rightarrow \frac{3x}{x}=10x^2-x

    \Rightarrow 3=10x^2-x
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    I get it now very much appreciated
 
 
 
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