Hello could anyone help me answer this and could you number the steps?

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    Calculate the ph at 298k of an aq solution of CH3COOH of concertration 0.100 mol dm-3 . (Ka = 1.74*10-5 mol dm-3 at 298k)
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    show us your attempt
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    (Original post by Hazel99)
    Calculate the ph at 298k of an aq solution of CH3OOH of concertration 0.100 mol dm-3 . (Ka = 1.74*10-5 mol dm-3 at 298k)
    http://chemistry.about.com/od/worked...phweakacid.htm
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    (Original post by Daniel Atieh)
    show us your attempt
    I don't know if this is right but I had a go.

    Ka= 1.74*10-5
    Conc= 0.1 M

    1.74*10-5 = (H+) / (HA) = 0.1 mol dm-3

    (H+)= 1.319090569*10-3

    10- 1.31..... = ph 0.996

    Please can you help me.
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    (Original post by Hazel99)
    Calculate the ph at 298k of an aq solution of CH3OOH of concertration 0.100 mol dm-3 . (Ka = 1.74*10-5 mol dm-3 at 298k)
    Methyl hydroperoxide?
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    (Original post by alow)
    Methyl hydroperoxide?
    Seems unlikely. There's likely a missing C.
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    (Original post by Kvothe the Arcane)
    Seems unlikely. There's likely a missing C.
    Yeah, I think I remember the Ka of ethanoic acid is about 1.8*10-5 too.
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    Deffo EtOOH, I always use 1.74 in class.
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    (Original post by alow;[url="tel:67756552")
    67756552[/url]]Methyl hydroperoxide?
    Are u trying to name CH3OOH??
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    (Original post by Hazel99)
    Are u trying to name CH3OOH??
    Yeah that's the name of CH3OOH. You've got the formula wrong, you mean CH3COOH.
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    (Original post by alow;[url="tel:67757604")
    67757604[/url]]Yeah that's the name of CH3OOH. You've got the formula wrong, you mean CH3COOH.
    Oh yeah, sorry about that
 
 
 
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