Show that 3/(x-2) + 4/(x-1) = 7x -11/(x-2)(x-1). Therefore solve the equation 3/(x-2) + 4/(x-1) = 7/x; I've done the first but I just need a prompt on how to do the second bit, I know it's probably really simple
Core 4 partial fractions Watch
- Thread Starter
- 23-09-2016 10:02
- 23-09-2016 11:11
Try restating the given equation in the second part by replacing the LHS with what you found in the first part of the question. Then cross-multiply the denominators. Then rearrange all the terms onto one side and you'll either be left with a quadratic, or (maybe) the term in x^2 will be zero...