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    A car was travelling at 30m/s. The driver applied the brakes to decelerate the car uniformly in 4.8 s.
    Calculate the braking distance?
    ???
    Have no clue
    It is involved with other sub questions like
    Calculate the deceleration which is, 6.25m/s^2
    And the braking force which is 5625N
    But how do you work out the braking distance
    In the answers, it says the answer is 73m BUT HOW DID THEY GET THAT?!?!
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    (Original post by Sanjith Hegde123)
    A car was travelling at 30m/s. The driver applied the brakes to decelerate the car uniformly in 4.8 s.
    Calculate the braking distance?
    ???
    Have no clue
    It is involved with other sub questions like
    Calculate the deceleration which is, 6.25m/s^2
    And the braking force which is 5625N
    But how do you work out the braking distance
    In the answers, it says the answer is 73m BUT HOW DID THEY GET THAT?!?!
    This is a question involving constant acceleration.

    The acceleration can be calculated using "definition" of acceleration formula, where v = 0

    a = (v - u)/t

    The braking distance can found using either
    s = 1/2(u)t ---- this is area under the v-t graph
    or
    v2 = u2 + 2as

    The braking force can is using F = ma.
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    (Original post by Sanjith Hegde123)
    A car was travelling at 30m/s. The driver applied the brakes to decelerate the car uniformly in 4.8 s.
    Calculate the braking distance?
    ???
    Have no clue
    It is involved with other sub questions like
    Calculate the deceleration which is, 6.25m/s^2
    And the braking force which is 5625N
    But how do you work out the braking distance
    In the answers, it says the answer is 73m BUT HOW DID THEY GET THAT?!?!
    Do a=(v-u)/t to get the deceleration and then use s=ut+1/2at^2 to get the displacement.


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