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ℓove
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At time t = 0, two balls A and B are projected vertically upwards. The ball A is projected vertically upwards with speed 2m/s from a point 50m above the horizontal ground. The ball B is projected vertically upwards from the ground with speed 20m/s. At time t = T seconds, the two balls are at the same vertical height, h metres, above the ground. The balls are modelled as particles moving freely under gravity.
I've got to the point where I have two equations:
Ball A -
h-50=2T+1/2(-9.8)t2
Ball B -
h=20T+1/2(-9.8)t2
What do I have to do now to solve h and T?
I've got to the point where I have two equations:
Ball A -
h-50=2T+1/2(-9.8)t2
Ball B -
h=20T+1/2(-9.8)t2
What do I have to do now to solve h and T?
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ℓove
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#2
username1256732
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#3
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#3
(Original post by ℓove)
At time t = 0, two balls A and B are projected vertically upwards. The ball A is projected vertically upwards with speed 2m/s from a point 50m above the horizontal ground. The ball B is projected vertically upwards from the ground with speed 20m/s. At time t = T seconds, the two balls are at the same vertical height, h metres, above the ground. The balls are modelled as particles moving freely under gravity.
I've got to the point where I have two equations:
Ball A -
h-50=2T+1/2(-9.8)t2
Ball B -
h=20T+1/2(-9.8)t2
What do I have to do now to solve h and T?
At time t = 0, two balls A and B are projected vertically upwards. The ball A is projected vertically upwards with speed 2m/s from a point 50m above the horizontal ground. The ball B is projected vertically upwards from the ground with speed 20m/s. At time t = T seconds, the two balls are at the same vertical height, h metres, above the ground. The balls are modelled as particles moving freely under gravity.
I've got to the point where I have two equations:
Ball A -
h-50=2T+1/2(-9.8)t2
Ball B -
h=20T+1/2(-9.8)t2
What do I have to do now to solve h and T?
h-(h-50)=20T+1/2(-9.8)T2 -(2T+ 1/2(-9.8)T2)
50=18T
T=50/18
Then we can solve
h=20*T+1/2(-9.8)T2 plugging in our T value
Please note, I havent checked that your equations are correct.
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ℓove
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#4
(Original post by mathematigeek)
This is simply simultaneous equations, and so, assuming your equations are correct, we can subtract Ball A from Ball B, giving:
h-(h-50)=20T+1/2(-9.8)T2 -(2T+ 1/2(-9.8)T2)
50=18T
T=50/18
Then we can solve
h=20*T+1/2(-9.8)T2 plugging in our T value
Please note, I havent checked that your equations are correct.
This is simply simultaneous equations, and so, assuming your equations are correct, we can subtract Ball A from Ball B, giving:
h-(h-50)=20T+1/2(-9.8)T2 -(2T+ 1/2(-9.8)T2)
50=18T
T=50/18
Then we can solve
h=20*T+1/2(-9.8)T2 plugging in our T value
Please note, I havent checked that your equations are correct.
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rahnaramzeen
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#5
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