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Quadratics and discriminant Watch

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    Find the possible solutions of the quadratic equation x^2+(3-m)x+5 = m^2
    where m is a constant, given that it has repeated roots.

    I worked out the discriminant which is b^2-4ac=0
    So (3-m)^2 -4(5) which gives me m^2-6m-11 =0
    Not sure what to do from here.
    Thanks!
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    (Original post by algebrax1)
    Find the possible solutions of the quadratic equation x^2+(3-m)x+5 = m^2
    where m is a constant, given that it has repeated roots.

    I worked out the discriminant which is b^2-4ac=0
    So (3-m)^2 -4(5) which gives me m^2-6m-11 =0
    Not sure what to do from here.
    Thanks!
    The quadratic expression should be equal to 0.
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    (Original post by algebrax1)
    Find the possible solutions of the quadratic equation x^2+(3-m)x+5 = m^2
    where m is a constant, given that it has repeated roots.

    I worked out the discriminant which is b^2-4ac=0
    So (3-m)^2 -4(5) which gives me m^2-6m-11 =0
    Not sure what to do from here.
    Thanks!
    a=1

b=3-m

c=5-m^2

    Now try again.
 
 
 
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