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# How do I resolve forces on a horizontal plane? Watch

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1. Two particles P and Q, of masses 5kg and 3kg respectively, are connected by a light inextensible string. Particle P is pulled by a horizontal force of magnitude 40N along a rough horizontal plane. The coefficient of friction between each particle and the plane is 0.2.

What's equation do I need to use to resolve the forces?
2. (Original post by ℓove)
Two particles P and Q, of masses 5kg and 3kg respectively, are connected by a light inextensible string. Particle P is pulled by a horizontal force of magnitude 40N along a rough horizontal plane. The coefficient of friction between each particle and the plane is 0.2.

What's equation do I need to use to resolve the forces?
Well so far there isn't a question.
The formulae you will use are F=ma, friction(max)=coefficient x R and R=mg
E.g. Considering P
R = 5g
Friction = 0.2x5g = 9.8 N
Do the same for Q

In terms of resolving forces the only forces opposing the 40N pulling force is the friction acting on each particle. Calculating the difference enables you to work out the effective force acting to pull the particles and deduce the acceleration using F=ma

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Updated: September 25, 2016
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