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Hard maths question suvat Watch

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    Cyclist travelling w/ constant acceleration passes 3 points A, B and C. AB = CD = 20M. The speed of a cyclist at A is 8m/s and at Bis 12m/s. What is its speed at c?
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    v=sqrt(u^(2)+2as) so v = 15ms^(-1) to 2 S.F.
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    (Original post by IGCSETANK)
    Cyclist travelling w/ constant acceleration passes 3 points A, B and C. AB = CD = 20M. The speed of a cyclist at A is 8m/s and at Bis 12m/s. What is its speed at c?
    Work out the time with from A to B with s=\frac{1}{2}(u+v)t and then find the acceleration. Then just use v^2=u^2+2as for the final speed.

    These aren't even the hard SUVAT questions...
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    I don't feel your question gives enough information as what is the relevance of the distance CD? I assume in the question you mean AB=BC in which case.

    Assuming the above is correct:
    v^2 = u^2+2as can be used with the initial parameters to get a acceleration. It can also be used again to find the speed at v. Using this assumption, I got the value of sqrt(224) which I hope helps.
 
 
 
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