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Really easy S2 question? I missed a lesson, so I don't understand.

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    A bag contains 4 red, 3 green, and 8 yellow beads. Five beads are selected at random from the bag without replacement. Find the probability that they are 2 red and 3 yellow
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    (Original post by APersonYo)
    A bag contains 4 red, 3 green, and 8 yellow beads. Five beads are selected at random from the bag without replacement. Find the probability that they are 2 red and 3 yellow
    Draw a tree diagram.
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    (Original post by Zacken)
    Draw a tree diagram.
    Ahahah awful advice. Finally figured it out. You would want to draw a tree diagram for this question? Good luck drawing a tree diagram for the 10 possible arrangements !!
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    (Original post by APersonYo)
    Ahahah awful advice. Finally figured it out. You would want to draw a tree diagram for this question? Good luck drawing a tree diagram for the 10 possible arrangements !!
    No, I wouldn't. But I don't fancy explaining binomial distributions to someone who missed the lesson on them, so resorted to reducing the problem to something that you did know how to do.
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    (Original post by APersonYo)
    Ahahah awful advice. Finally figured it out. You would want to draw a tree diagram for this question? Good luck drawing a tree diagram for the 10 possible arrangements !!
    Is it 16/143 ?
 
 
 
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