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Differentiation help

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    I don't understand how to do the 2/x bit could anyone explain and help please would be much appreciated
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    (Original post by junayd1998)
    I don't understand how to do the 2/x bit could anyone explain and help please would be much appreciated
    \dfrac{2}{x} = 2x^{-1} and you know how to differentiate x^n.
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    (Original post by Zacken)
    \dfrac{2}{x} = 2x^{-1} and you know how to differentiate x^n.
    oh alright thanks yeah you will get -2^-2
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    (Original post by junayd1998)
    I don't understand how to do the 2/x bit could anyone explain and help please would be much appreciated
    \frac{2}{x}=2x^{-1}
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    (Original post by RDKGames)
    \frac{2}{x}=2x^{-1}
    yep thank you.
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    (Original post by junayd1998)
    oh alright thanks yeah you will get -2^-2
    Typo, I presume? You should then get \frac{d}{dx} (2x^{-1}) = 2(-1)x^{-1-1} = -2x^{-2}.
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    (Original post by Zacken)
    Typo, I presume? You should then get \frac{d}{dx} (2x^{-1}) = 2(-1)x^{-1-1} = -2x^{-2}.
    Oh yeah sorry forgot to add the x (typo) yep -2x^-2
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    (Original post by junayd1998)
    Oh yeah sorry forgot to add the x (typo) yep -2x^-2
    Yep, that's right
 
 
 
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