You are Here: Home

# Calculate the ph of CH3COOH of conc. 0.100 moldm-3 Watch

Announcements
1. (Ka =1.74 *10-5 at 298k)

Conc. 0.100

1.74*10-5 =(H+)/(HA)= 0.1 moldm-3
(H+)= 1.319090569*10-3
10-1.31...=pH 0.996

???? Is this right
2. (Original post by Hazel99)
(Ka =1.74 *10-5 at 298k)

Conc. 0.100

1.74*10-5 =(H+)/(HA)= 0.1 moldm-3
(H+)= 1.319090569*10-3
10-1.31...=pH 0.996

???? Is this right
[H+]^2 = (Ka x [HA])
[H+] = square root of (Ka x [HA])
the square root of 1.74x10-5 x 0.100 = 1.319x10-3
-log(1.319x10-3) = 2.88

3. (Original post by Louisss;[url="tel:67768910")
67768910[/url]][H+]^2 = (Ka x [HA])
[H+] = square root of (Ka x [HA])
the square root of 1.74x10-5 x 0.100 = 1.319x10-3
-log(1.319x10-3) = 2.88

Thank you 😊

TSR Support Team

We have a brilliant team of more than 60 Support Team members looking after discussions on The Student Room, helping to make it a fun, safe and useful place to hang out.

This forum is supported by:
Updated: September 26, 2016
Today on TSR

This is how Oxbridge students do it.

### This compliment left me speechless...

Discussions on TSR

• Latest
• ## See more of what you like on The Student Room

You can personalise what you see on TSR. Tell us a little about yourself to get started.

• Poll
Discussions on TSR

• Latest
• ## See more of what you like on The Student Room

You can personalise what you see on TSR. Tell us a little about yourself to get started.

• The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.