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Calculate the ph of CH3COOH of conc. 0.100 moldm-3 Watch

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    (Ka =1.74 *10-5 at 298k)

    Conc. 0.100

    1.74*10-5 =(H+)/(HA)= 0.1 moldm-3
    (H+)= 1.319090569*10-3
    10-1.31...=pH 0.996

    ???? Is this right
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    (Original post by Hazel99)
    (Ka =1.74 *10-5 at 298k)

    Conc. 0.100

    1.74*10-5 =(H+)/(HA)= 0.1 moldm-3
    (H+)= 1.319090569*10-3
    10-1.31...=pH 0.996

    ???? Is this right
    [H+]^2 = (Ka x [HA])
    [H+] = square root of (Ka x [HA])
    the square root of 1.74x10-5 x 0.100 = 1.319x10-3
    -log(1.319x10-3) = 2.88

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    (Original post by Louisss;[url="tel:67768910")
    67768910[/url]][H+]^2 = (Ka x [HA])
    [H+] = square root of (Ka x [HA])
    the square root of 1.74x10-5 x 0.100 = 1.319x10-3
    -log(1.319x10-3) = 2.88

    Thank you 😊
 
 
 
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