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Help me impress my lecturer Watch

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    He gave everyone a really hard differential equation to solve which noone could do in the first lecture
    Can someone solve it for me: x*(dy/dx) + y = 1
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    You're gonna take all the credit from someone else's work aren't you
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    (Original post by UWS)
    You're gonna take all the credit from someone else's work aren't you
    it isnt uncommon, I head many famous inventions and discoveries are credited to the wrong ppl :lol:
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    (Original post by I am a Lie)
    He gave everyone a really hard differential equation to solve which noone could do in the first lecture
    Can someone solve it for me: x*(dy/dx) + y = 1
    I'll give you a clue:  \frac{d}{dx} f(x,y) = x\frac{dy}{dx} + y where f(x,y) is a very simple function of x and y that you need to find.
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    (Original post by Plagioclase)
    I'll give you a clue:  \frac{d}{dx} f(x,y) = x\frac{dy}{dx} + y where f(x,y) is a very simple function of x and y that you need to find.
    looool idek wat dat means:rofl:
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    (Original post by I am a Lie)
    looool idek wat dat means:rofl:
    Okay sorry, possibly wasn't the clearest way of saying it! I'm assuming that you've done implicit differentiation because if you haven't, you probably won't be able to work this out. What's I'm trying to say is that there is a function that, when you differentiate it, you get the left hand side of your equation. Which then makes it extremely easy to solve. The tricky bit is working out what the function is and you should be able to work it out if you know how to do implicit differentiation.
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    (Original post by I am a Lie)
    He gave everyone a really hard differential equation to solve which noone could do in the first lecture
    Can someone solve it for me: x*(dy/dx) + y = 1
    Not at all hard! Divide through by x and find the PI which should be e^{\int \frac{1}{x}}.
    Spoiler:
    Show
    :troll:
    But the general solution is y=1+\frac{A}{x}. NOW GO IMPRESS UR LECTURER M8
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    (Original post by RDKGames)
    Not at all hard! Divide through by x and find the PI which should be e^{\int \frac{1}{x}}.
    Spoiler:
    Show
    :troll:
    urm how about the y???
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    (Original post by RDKGames)
    Not at all hard! Divide through by x and find the PI which should be e^{\int \frac{1}{x}}.
    Spoiler:
    Show
    :troll:
    But the general solution is y=1+\frac{A}{x}. NOW GO IMPRESS UR LECTURER M8
    wtf is A?
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    ....and why would ur lecturer be impressed by this?
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    (Original post by I am a Lie)
    wtf is A?
    m8 I arrived here to give you an answer, NOT a lesson. A is any constant. You need a certain condition if you want it to be a number
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    (Original post by Rhaenys10)
    ....and why would ur lecturer be impressed by this?
    a class of like 80 people couldnt do it
    If i was the only one who could id be cool
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    Bake him a cake.
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    (Original post by Rhaenys10)
    ....and why would ur lecturer be impressed by this?
    I'm surprised as well. I bet he's doing a foundation maths course (or something mathsy) at a uni and he's on his first year, because this is a very simple problem indeed which pops up as the first thing in one of the Further Maths A-Level modules lol
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    (Original post by RDKGames)
    I'm surprised as well. I bet he's doing a foundation maths course (or something mathsy) at a uni and he's on his first year, because this is a very simple problem indeed which pops up as the first thing in Further Maths A-Level lol
    Nope doing pure maths, recieved a B for a level matsh( which isnt great but I did get 4 As in my modules) did not do further maths
    Plus I haven't touched maths for over 3 months
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    (Original post by RDKGames)
    I'm surprised as well. I bet he's doing a foundation maths course (or something mathsy) at a uni and he's on his first year, because this is a very simple problem indeed which pops up as the first thing in one of the Further Maths A-Level modules lol
    yeah
    probably)
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    I thought this was going to be a help me seduce my lecturer thread
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    (Original post by Rhaenys10)
    yeah
    probably)
    im sorry im not as smart as u
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    (Original post by Pinkberry_y)
    I thought this was going to be a help me seduce my lecturer thread
    SAME
    I actually went on giphy looking for a cleavage gif but nah=)))
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    (Original post by Rhaenys10)
    SAME
    I actually went on giphy looking for a cleavage gif but nah=)))
    LOL!
 
 
 
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