metaljoe
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#1
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Does e^ln = 1?
Any help would be appreciated!!
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Plagioclase
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#2
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(Original post by metaljoe)
Does e^ln = 1?
Any help would be appreciated!!
e to the ln of what? It's true that e^{ln|x|}=|x| but that's only equal to 1 for x=1.
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Kevin De Bruyne
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(Original post by metaljoe)
Does e^ln = 1?
Any help would be appreciated!!
e^ln is an invalid expression - ln is not taking in any arguments.
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Boss_Rhythm
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Yes.
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k.russell
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e^Ln(1) = 1
e^ln doesn't mean anything, you can't have a ln without a value of some kind
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Shipreck
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#6
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ln(1) = 0, e^0 = 1 so e^l^n^(^1^)  = 1
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metaljoe
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#7
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The question I was answering was:

Solve the following equations, giving your answers in exact form:

ln | 3x - 1 | = 4

I took both sides to the power of e leaving:

e^ln|3x-1| = e^4

So I was wondering if e^ln = 1 times what ever is the power of e^ln?
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NotNotBatman
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#8
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(Original post by metaljoe)
The question I was answering was:

Solve the following equations, giving your answers in exact form:

ln | 3x - 1 | = 4

I took both sides to the power of e leaving:

e^ln|3x-1| = e^4

So I was wondering if e^ln = 1 times what ever is the power of e^ln?
You have to have the natural log of something.  e^x and  ln(x) are inverses and  f^{-1}(fg(x)) = g(x)

so if f(x) = e^x, then  f^{-1}(x) =ln(x)

so, e^ln|3x-1| = |3x-1|
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metaljoe
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#9
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(Original post by NotNotBatman)
You have to have the natural log of something.  e^x and  ln(x) are inverses and  f^{-1}(fg(x)) = g(x)

so if f(x) = e^x, then  f^{-1}(x) =ln(x)

so, e^ln|3x-1| = |3x-1|
Cheers buddy!!!
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metaljoe
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#10
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Thanks everyone all sorted now!!!!
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