Does e^ln = 1?

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    Does e^ln = 1?
    Any help would be appreciated!!
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    (Original post by metaljoe)
    Does e^ln = 1?
    Any help would be appreciated!!
    e to the ln of what? It's true that e^{ln|x|}=|x| but that's only equal to 1 for x=1.
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    (Original post by metaljoe)
    Does e^ln = 1?
    Any help would be appreciated!!
    e^ln is an invalid expression - ln is not taking in any arguments.
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    Yes.
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    e^Ln(1) = 1
    e^ln doesn't mean anything, you can't have a ln without a value of some kind
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    ln(1) = 0, e^0 = 1 so e^l^n^(^1^)  = 1
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    The question I was answering was:

    Solve the following equations, giving your answers in exact form:

    ln | 3x - 1 | = 4

    I took both sides to the power of e leaving:

    e^ln|3x-1| = e^4

    So I was wondering if e^ln = 1 times what ever is the power of e^ln?
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    (Original post by metaljoe)
    The question I was answering was:

    Solve the following equations, giving your answers in exact form:

    ln | 3x - 1 | = 4

    I took both sides to the power of e leaving:

    e^ln|3x-1| = e^4

    So I was wondering if e^ln = 1 times what ever is the power of e^ln?
    You have to have the natural log of something.  e^x and  ln(x) are inverses and  f^{-1}(fg(x)) = g(x)

    so if f(x) = e^x, then  f^{-1}(x) =ln(x)

    so, e^ln|3x-1| = |3x-1|
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    (Original post by NotNotBatman)
    You have to have the natural log of something.  e^x and  ln(x) are inverses and  f^{-1}(fg(x)) = g(x)

    so if f(x) = e^x, then  f^{-1}(x) =ln(x)

    so, e^ln|3x-1| = |3x-1|
    Cheers buddy!!!
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    Thanks everyone all sorted now!!!!
 
 
 
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