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Physics/Maths - [Gradient - Help]

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    Posting an image below:

    I done the usual but it saids my answer is wrong.
    The usual as in m = change in y/change in x
    I think it has something to do with the graph not starting from 0.
    I put the y intercept as 10 but that is wrong too. I doen all the other ones when it starts at 0 so im guessing thats the problem.

    Thanks
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    Name:  Capture.PNG
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    change in y = -2, , change in x = 50, m = \frac{-2}{50} = \frac{-1}{25}

    The y intercept doesn't matter at all when you are finding the gradient. If you are trying to find the equation of the line theny = mx + c, m =  \frac{-1}{25}, c = 10

    therefore  y = \frac{-1}{25}x + 10
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    (Original post by AdeptDz)
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    maybe the change in x needs to be negative?

    no idea what you posted - it doesn't make any sense
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    (Original post by Maths is Life)
    maybe the change in x needs to be negative?

    no idea what you posted - it doesn't make any sense
    Basically:
    Gradient and y-intercept of tht graph i just posted..
    And I done that
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    (Original post by Shipreck)
    change in y = -2, , change in x = 50, m = \frac{-2}{50} = \frac{-1}{25}

    The y intercept doesn't matter at all when you are finding the gradient. If you are trying to find the equation of the line theny = mx + c, m = \frac{-1}{25}, c = 10

    therefore  y = \frac{-1}{25}x + 10
    Ohh damn, thanks I see what i done wrong
    I didn't see the 50 i thought it was 0 so i put 100 instead of 50.
    Thanks
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    (Original post by Shipreck)
    change in y = -2, , change in x = 50, m = \frac{-2}{50} = \frac{-1}{25}

    The y intercept doesn't matter at all when you are finding the gradient. If you are trying to find the equation of the line theny = mx + c, m = \frac{-1}{25}, c = 10

    therefore  y = \frac{-1}{25}x + 10
    It asks for the y intercept and I did put 10 but then as a hint it said
    'remember the graph doesn't start from 0'
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    (Original post by AdeptDz)
    It asks for the y intercept and I did put 10 but then as a hint it said
    'remember the graph doesn't start from 0'
    If 10 wasn't the answer I'd assume they mean to continue the line backwards to when the current drawn is 0, then find the voltage at that point.
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    (Original post by JN17)
    If 10 wasn't the answer I'd assume they mean to continue the line backwards to when the current drawn is 0, then find the voltage at that point.
    Ahh yh true, thanks
    Spoiler:
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    I'll try that in a bit.. started another one
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    (Original post by AdeptDz)
    It asks for the y intercept and I did put 10 but then as a hint it said
    'remember the graph doesn't start from 0'
    Woops, didn't see that xD.y - 10 = -\frac{1}{25}(x - 50), y = -\frac{x}{25} + 2 + 10, y = -\frac{x}{25} +12
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    (Original post by Shipreck)
    Woops, didn't see that xD.y - 10 = -\frac{1}{25}(x - 50), y = -\frac{x}{25} + 2 + 10, y = -\frac{x}{25} +12
    sorry, this is correct
    Thanks!
    so it is 12
 
 
 
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