Maths help!!

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    Please help! Find the equation of the line perpendicular to line y= x-4 passing through (-1,-2)
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    (Original post by Sukjeetsandhu)
    Please help! Find the equation of the line perpendicular to line y= x-4 passing through (-1,-2)
    So what would the perpendicular gradient be to the gradient of 1?

    Then use y-y_1=m'(x-x_1)
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    (Original post by RDKGames)
    So what would the perpendicular gradient be to the gradient of 1?

    Then use y-y_1=m'(x-x_1)
    You go glen coco.

    -ive reciprocal ftw
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    (Original post by Maths is Life)
    You go glen coco.

    -ive reciprocal ftw
    lol wat
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    (Original post by RDKGames)
    lol wat
    Didn't you mean negative 1?

    The normal or perpendicular gradient is the negative reciprocal of the gradient.

    Glen Coco??? Mean Girls?
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    (Original post by Maths is Life)
    Didn't you mean negative 1?

    The normal or perpendicular gradient is the negative reciprocal of the gradient.

    Glen Coco??? Mean Girls?
    Yeah, I think you misread lol. I said what would the the perp gradient be to the gradient of 1, so -1 is the perp gradient to 1.
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    (Original post by RDKGames)
    Yeah, I think you misread lol. I said what would the the perp gradient be to the gradient of 1, so -1 is the perp gradient to 1.
    Meh just a bit of banter.

    This guy will get 100UMS if he's asking questions this early
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    (Original post by Maths is Life)
    Meh just a bit of banter.

    This guy will get 100UMS if he's asking questions this early
    Just wait until May when he asks the same question again.
 
 
 
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