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Maths help!!

1. Please help! Find the equation of the line perpendicular to line y= x-4 passing through (-1,-2)
2. (Original post by Sukjeetsandhu)
Please help! Find the equation of the line perpendicular to line y= x-4 passing through (-1,-2)
So what would the perpendicular gradient be to the gradient of 1?

Then use
3. (Original post by RDKGames)
So what would the perpendicular gradient be to the gradient of 1?

Then use
You go glen coco.

-ive reciprocal ftw
4. (Original post by Maths is Life)
You go glen coco.

-ive reciprocal ftw
lol wat
5. (Original post by RDKGames)
lol wat
Didn't you mean negative 1?

The normal or perpendicular gradient is the negative reciprocal of the gradient.

Glen Coco??? Mean Girls?
6. (Original post by Maths is Life)
Didn't you mean negative 1?

The normal or perpendicular gradient is the negative reciprocal of the gradient.

Glen Coco??? Mean Girls?
Yeah, I think you misread lol. I said what would the the perp gradient be to the gradient of 1, so -1 is the perp gradient to 1.
7. (Original post by RDKGames)
Yeah, I think you misread lol. I said what would the the perp gradient be to the gradient of 1, so -1 is the perp gradient to 1.
Meh just a bit of banter.

This guy will get 100UMS if he's asking questions this early
8. (Original post by Maths is Life)
Meh just a bit of banter.

This guy will get 100UMS if he's asking questions this early
Just wait until May when he asks the same question again.

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