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Phase difference/ path difference

    • Thread Starter

    So I'm doing homework on superposition and polarisation and there's a question on phase difference/ path difference that i have no idea how to answer. These are the questions:

    b) path differences give rise to phase differences. By how much do the following change the phase difference?
    (i) 1 wavelength
    (ii) wavelength/2
    (iii) 3 wavelength/4

    c) What path differences would give the following phase differences?

    (i) 90 degrees
    (ii) 120 degrees
    (iii)540 degrees

    Any help would be great!!

    it's a linear relationship

    Dφ(in degrees)=360(Dl/λ)

    so... if difference in path (Dl) = 0λ
    then difference in phase (Dφ) = 0 degrees

    if difference in path = 100λ
    then difference in phase = 36000 degrees

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