Hey there! Sign in to join this conversationNew here? Join for free

Phase difference/ path difference Watch

Announcements
    • Thread Starter
    Offline

    0
    ReputationRep:
    So I'm doing homework on superposition and polarisation and there's a question on phase difference/ path difference that i have no idea how to answer. These are the questions:

    b) path differences give rise to phase differences. By how much do the following change the phase difference?
    (i) 1 wavelength
    (ii) wavelength/2
    (iii) 3 wavelength/4

    c) What path differences would give the following phase differences?

    (i) 90 degrees
    (ii) 120 degrees
    (iii)540 degrees

    Any help would be great!!
    Offline

    19
    ReputationRep:
    it's a linear relationship

    Dφ(in degrees)=360(Dl/λ)

    so... if difference in path (Dl) = 0λ
    then difference in phase (Dφ) = 0 degrees

    if difference in path = 100λ
    then difference in phase = 36000 degrees

    etc.
 
 
 
  • See more of what you like on The Student Room

    You can personalise what you see on TSR. Tell us a little about yourself to get started.

  • Poll
    Break up or unrequited love?
  • See more of what you like on The Student Room

    You can personalise what you see on TSR. Tell us a little about yourself to get started.

  • The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

    Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

    Quick reply
    Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.