First ionisation energy equations.. help?! Watch
1st IE is just the energy required to remove one mole of electrons from one mole of atoms in the gas phase. The more tightly bound the highest energy electron is, the higher the 1st IE.
I don't think you ever need to do calculations with ionisation energy, you just have to be able to compare data and explain it.
Also, higher energy level requires LESS energy to remove an electron.
I've just started year one A levels and I've been set questions on the first chapter of the textbook. There's some easy questions about TOF mass spectrometry and basic atomic configuration, but we've been set the end of chapter questions to do when were only on page 10, we haven't covered half the chapter. The teacher expects us to do ALL the questions, but most of them are about "first ionisation energy"? And the equations and rearranging it.. I've read the textbook, explanations online and nothing is going in, I'm tired anyway and I just don't understand it for some reason? I'm normally good at learning new information but it's really stressing me out and I need to somehow answer really obscure questions on concepts I haven't been taught yet and don't understand. Can anyone try and dumb it down for me a bit? Thanks
CheeseIsVeg & anyone else who can actually do chemistry (not me)
Equations relating first ionisation energy usually are in the form: X (g) --> X^+(g) + e^-
The electron removed = e^-
Hope this makes sense, feel free to post the question, ask more questions
I'm not going to confuse you by telling you the actual charge in Coulombs, even though I really want to
Read this: http://www.chemguide.co.uk/atoms/properties/ies.html
What does it have to do to get the number of electrons of the ion in the question?
So Aluminium has 13 electrons
These lie in the 1s2 2s2 2p6 3s2 3p1 sub shells
the question ends in 3s1
I have bolded where 3s1 is in aluminium's full electronic configuration
How many ionisations is this?Well 3p1 = 1, to get to 3s1 we then knock off another electron, therefore it would be 2nd ionisation (2 electrons lost )