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# I don't get this watch

1. What is the apparent weight during take-off of an astronaut whose actual weight is 750N if the resultant upward acceleration is 5g?
They say the answer is 4500 by F=m(g+5g)
But why? T.T
5g is an upward acceleration while g is downwards why are they added??
2. (Original post by Posama)
What is the apparent weight during take-off of an astronaut whose actual weight is 750N if the resultant upward acceleration is 5g?
They say the answer is 4500 by F=m(g+5g)
But why? T.T
5g is an upward acceleration while g is downwards why are they added??
F = mg + ma.
F = apparent weight in newtons
m = the mass of the object
g is the acceleration due to gravity (9.8 meters per second squared on Earth's surface)
a is the acceleration of the object

On the answer they just factorised m so
F= m(g+a)
a = 5g
so m(g+5g)

See what you can do from there

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