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    What is the apparent weight during take-off of an astronaut whose actual weight is 750N if the resultant upward acceleration is 5g?
    They say the answer is 4500 by F=m(g+5g)
    but why?
    5g is upwards and g is downwards so isn't one of them supposed to become negative??
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    Have you tried looking at it in terms of F=ma ?
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    (Original post by Posama)
    What is the apparent weight during take-off of an astronaut whose actual weight is 750N if the resultant upward acceleration is 5g?
    They say the answer is 4500 by F=m(g+5g)
    but why?
    5g is upwards and g is downwards so isn't one of them supposed to become negative??
    Because in order to accelerate him upwards at 5g he will be pushed in to the seat with a force of 5mg + his weight which is mg
 
 
 
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