# FP1 - [Proof]Watch

#1

So I done the first bit

Step 1
Prove true for n=1 and n = 2

Both true

Step 2
Assume true for n=k and n=k+1, if true for n=k and n=k+1 then true for n=k+2

.....
....
....
Step 1 + Step 2 proves true for all n by induction

I don't know what to do now, may someone help me please
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2 years ago
#2
You have to show that .
You are correct so far and you can get to the required result from the step you're at.
1
#3
(Original post by B_9710)
You have to show that .
Yeh i know that bit thanks, i just don't know how to make
show
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#4
(Original post by B_9710)
You have to show that .
You are correct so far and you can get to the required result from the step you're at.
I expanded it but i remember my teacher saying don't expand it unless you absolutely have to, and i can't tell if i have to or not like if there is another option
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2 years ago
#5
You know you need a , so look for ways to get that. What can you do with 6 and 9?
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#6
(Original post by NotNotBatman)
You know you need a , so look for ways to get that. What can you do with 6 and 9?
take out a factor of 3?
0
2 years ago
#7
divide them by 2 and 3? to get 3?
Don't divide, but factorise. Remember you can't change the value.

9 can be written as 3^x right?

And then what happens with the 3?
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#8
(Original post by NotNotBatman)
Don't divide, but factorise. Remember you can't change the value.

9 can be written as 3^x right?

And then what happens with the 3?
Yeh my bad, i editted the post after you checked it im guessing

ohh, let me try see what i get now
Thanks
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#9
So would it be
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2 years ago
#10
So would it be
Rather than taking factorising 3 in the last step, do you notice that you'll get
in the first term and in the second term there is a remembering that

Also you've written it a bit wrong. It is

remember it's 3^k, not 3k, so you can't factorise 3 like that.
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#11
(Original post by NotNotBatman)
Rather than taking factorising 3 in the last step, do you notice that you'll get
in the first term and in the second term there is a remembering that

Also you've written it a bit wrong. It is

remember it's 3^k, not 3k, so you can't factorise 3 like that.
cool so:
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2 years ago
#12
cool so:
The adding power rule only applies when it's the same base, so

So you want on the first term; , so the powers of 3 can be added. do the same with

But leave the brackets (k-1) and (k-2) for now.
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#13
(Original post by NotNotBatman)
The adding power rule only applies when it's the same base, so

So you want on the first term; , so the powers of 3 can be added. do the same with

But leave the brackets (k-1) and (k-2) for now.
Would it be

so
0
2 years ago
#14
Would it be

so
yes, then you can add the powers of 3 on each individual term.
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#15
Would it be

so
so
0
2 years ago
#16
so
Yes, then you can factorise.
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#17
(Original post by NotNotBatman)
Yes, then you can factorise.

Got a feeling i did that wrong as idk where to put the 2
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2 years ago
#18

Got a feeling i did that wrong as idk where to put the 2
Factorise the whole thing, so use a big bracket and leave the 2 on the first term, it doesn't matter which way around it's multiplied.

when you multiply out it's the same right?
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#19
so
(Original post by NotNotBatman)
Yes, then you can factorise.
1sec, let me have another go
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#20

there
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