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A2 Maths C3 questions

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    Change one value in the expression so that there is a linear divisor in the remainder when simplified
    x^3-2x^2+6x-8/x^2+3x-4
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    (Original post by YUANHANGCHEN)
    Change one value in the expression so that there is a linear divisor in the remainder when simplified
    x^3-2x^2+6x-8/x^2+3x-4
    so im assuming you done the long division and got as far as;

     \displaystyle \frac{x^3 -2x^2 + 6x - 8}{x^2 +3x -4} \: = \: x- 5 + \frac{25x - 28}{x^2 + 3x -4}

    well if I was to tell you that for some value "a" ;  \displaystyle \frac{x^3 -2x^2 + 6x - a}{x^2 +3x -4} \: = \: x- 5 + \frac{25x - 20 - a}{x^2 + 3x -4} , does that help any?
 
 
 
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