A2 Maths C3 questions Watch

YUANHANGCHEN
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Change one value in the expression so that there is a linear divisor in the remainder when simplified
x^3-2x^2+6x-8/x^2+3x-4
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DylanJ42
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(Original post by YUANHANGCHEN)
Change one value in the expression so that there is a linear divisor in the remainder when simplified
x^3-2x^2+6x-8/x^2+3x-4
so im assuming you done the long division and got as far as;

 \displaystyle \frac{x^3 -2x^2 + 6x - 8}{x^2 +3x -4} \: = \: x- 5 + \frac{25x - 28}{x^2 + 3x -4}

well if I was to tell you that for some value "a" ;  \displaystyle \frac{x^3 -2x^2 + 6x - a}{x^2 +3x -4} \: = \: x- 5 + \frac{25x - 20 - a}{x^2 + 3x -4} , does that help any?
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