What do you think?
if you draw a boat with a line going straight up the page 5cm long to represent the engine thrust, a line 2cm long from the arrow head of the first arrow but this time directly right across the page. drawing a line from the base of the first arrow to the point of the last ( the one going right) will be the resultant. measuring this will give you its magnitude. measuring the angle will give you the the direction in "degrees from the vertical". honestly i'd watch someone do " vector resolution with to scale drawing" as seeing it written might not make a lot of sense. the acceleration is Force over mass so Resultant/ 1000.
You can also do the question with contrived mathematics.
The resultant velocity can be found with pythagoras. R^2 = 50^2 + 20^2 so R = squrt(2900) ==53.85N
The angle can be found using arctan(20/50) == 21.8 degrees from the vertical to the right.
if F=MA the F/M=A so 53.85/1000 = 0.05385 ms^-2 is the acceleration
arctan is just the proper way to write tan^-1
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