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Differential equation question

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    Hi guys,Could someone help me with finding the solution to dy/dx = x + xy (You don't need to make y the subject) The answer is ln (1+y) = x^2/2 +c I can see how the answer is the above (using differentiation) but can't seem to find how to go the other way. Thanks!!
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    You can rewrite x+xy as x(1+y). Do you know where to go from there?
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    (Original post by NeverLucky)
    You can rewrite  x+xy  as  x(1+y). Do you know where to go from there?
    Oh my goodness, I just saw it. I would separate the variables into
    1/(1+y) . dy = x . dx

    and then integrate each side to get
    ln (1+y) = x^2/2 + c

    Thank you for your help! By the way, how did you format the equations so it looks nicer?
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    (Original post by dyuunn)
    Oh my goodness, I just saw it. I would separate the variables into
    1/(1+y) . dy = x . dx

    and then integrate each side to get
    ln (1+y) = x^2/2 + c

    Thank you for your help! By the way, how did you format the equations so it looks nicer?
    Yep, well done. It's using LaTex to write the equations. There's a page on TSR showing how to write in LaTeX if you want to use it.
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    (Original post by NeverLucky)
    Yep, well done. It's using LaTex to write the equations. There's a page on TSR showing how to write in LaTeX if you want to use it.
    Awesome! Thank you once again.
 
 
 
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