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hello654321
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A straight line graph goes through (0,8) and (6,0). Write its equation in the form ax+by=c, where a, b, and c are constants.

Please give the method.
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hello654321
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quick please
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hello654321
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bump
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ksj.11
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c is 8


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asinghj
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(Original post by hello654321)
A straight line graph goes through (0,8) and (6,0). Write its equation in the form ax+by=c, where a, b, and c are constants.

Please give the method.
1) find gradient:
 m = \frac{y1-y2}{x1-x2}

2) Find equation and rearrange:
 y - y1 = m(x-x1)
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hello654321
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(Original post by asinghj)
1) find gradient:
 m = \frac{y1-y2}{x1-x2}

2) Find equation and rearrange:
 y - y1 = m(x-x1)
0,8 6,0
That isn't the right method i don't think...
gradient is 0-8/6-0 = -8/6

y - 8 = -8/6(x-0)
y-8= -8/6x - 0
+8
y= -8/6 x + 8 ???

this isn't the form ax+by=c and also i checked the answer and its 4x+3y=24??
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K-Man_PhysCheM
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(Original post by hello654321)
0,8 6,0
That isn't the right method i don't think...
gradient is 0-8/6-0 = -8/6

y - 8 = -8/6(x-0)
y-8= -8/6x - 0
+8
y= -8/6 x + 8 ???

this isn't the form ax+by=c and also i checked the answer and its 4x+3y=24??
 - \frac{8}{6} simplifies to  - \frac{4}{3}. Then multiply the whole expression by the denominator of the fraction, rearrange into the required form, and you get the answer.
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hello654321
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(Original post by K-Man_PhysCheM)
 - \frac{8}{6} simplifies to  - \frac{4}{3}. Then multiply the whole expression by the denominator of the fraction, rearrange into the required form, and you get the answer.
ahhh i see thanks!
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