# Maths helpWatch

#1
A straight line graph goes through (0,8) and (6,0). Write its equation in the form ax+by=c, where a, b, and c are constants.

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#2
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#3
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2 years ago
#4
c is 8

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2 years ago
#5
(Original post by hello654321)
A straight line graph goes through (0,8) and (6,0). Write its equation in the form ax+by=c, where a, b, and c are constants.

2) Find equation and rearrange:
0
#6
(Original post by asinghj)

2) Find equation and rearrange:
0,8 6,0
That isn't the right method i don't think...

y - 8 = -8/6(x-0)
y-8= -8/6x - 0
+8
y= -8/6 x + 8 ???

this isn't the form ax+by=c and also i checked the answer and its 4x+3y=24??
0
2 years ago
#7
(Original post by hello654321)
0,8 6,0
That isn't the right method i don't think...

y - 8 = -8/6(x-0)
y-8= -8/6x - 0
+8
y= -8/6 x + 8 ???

this isn't the form ax+by=c and also i checked the answer and its 4x+3y=24??
simplifies to . Then multiply the whole expression by the denominator of the fraction, rearrange into the required form, and you get the answer.
1
#8
(Original post by K-Man_PhysCheM)
simplifies to . Then multiply the whole expression by the denominator of the fraction, rearrange into the required form, and you get the answer.
ahhh i see thanks!
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