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1. A straight line graph goes through (0,8) and (6,0). Write its equation in the form ax+by=c, where a, b, and c are constants.

3. bump
4. c is 8

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5. (Original post by hello654321)
A straight line graph goes through (0,8) and (6,0). Write its equation in the form ax+by=c, where a, b, and c are constants.

2) Find equation and rearrange:
6. (Original post by asinghj)

2) Find equation and rearrange:
0,8 6,0
That isn't the right method i don't think...

y - 8 = -8/6(x-0)
y-8= -8/6x - 0
+8
y= -8/6 x + 8 ???

this isn't the form ax+by=c and also i checked the answer and its 4x+3y=24??
7. (Original post by hello654321)
0,8 6,0
That isn't the right method i don't think...

y - 8 = -8/6(x-0)
y-8= -8/6x - 0
+8
y= -8/6 x + 8 ???

this isn't the form ax+by=c and also i checked the answer and its 4x+3y=24??
simplifies to . Then multiply the whole expression by the denominator of the fraction, rearrange into the required form, and you get the answer.
8. (Original post by K-Man_PhysCheM)
simplifies to . Then multiply the whole expression by the denominator of the fraction, rearrange into the required form, and you get the answer.
ahhh i see thanks!

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